# SOLUTION: Penn State University Average Cycle Time Safety and Methods Essay

Attached.

SAFETY AND METHODS

1

Name of Student
Course Title
Institution
Instructor
Date of Submission

SAFETY AND METHODS

1. Conduction of Span Study
A. Average Cycle Time:
1st Element:

= (0.44 + 0.5 + 0.43 + 0.45 + 0.48 +0.46)/ 6
=0.46 minutes

2nd Element:
= (1.5+258+1.47+1.51+1.49+1.52)/6
=44.24 minutes

3rd Element:

= (0.84+0.89+0.77+0.83+0.85+0.8) / 6
=0.83 minutes

4th Element:

= (1.1+1.14+1.08+1.2+1.16+1.26)/6
=1.15 minutes

B. Normal span = (Avg element-time) * (Performance rating/100)

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SAFETY AND METHODS

1st Element

Normal span = (0.46)*(85/100)
= 0.39 minutes

2nd Element

Normal span = (44.24)*(100/100)
= 44.24minutes

3rd Element

Normal span = (0.83)*(110/100)
=0.913 minutes

4th Element

Normal span = (1.15)*(95/100)
= 1.09 minutes

C. Std span = 1+ Remuneration factors) * Normal span

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SAFETY AND METHODS

ST1= 0.391+1.15*0.46
= 0.92
ST2= 44. 248+1.15*44.248
= 95. 1332
ST3= 0.913+1.15*0.83
= 1.8675
ST4= 1.0982+1.15* 1.156
= 2.4276
D. Banner span , ST
15% remuneration of achievement span
i.

ST= 0.391+1.15*0.391
= 0.84

ii.

ST= 44. 25+1.15*44.248
= 95. 13

iii.

ST= 0.913+1.15*0.913
= 1.962

iv.

ST= 1.0982+1.15*1.0982
=2.36113

E. Parts executed in 8-hour shift
N=total span/ST
Therefore,
N1= 8*60/0.8406
571. 020 parts

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SAFETY AND METHODS

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N2= 480/95.1332
= 5.045 approximately 6 parts
N3= 480/1.962 = 244. 64
Approximately 245 parts
N4= 480/2.36113 = 203.29 parts
Approximately 204 parts
F.

Normal

Allowance

Standard

Element span

factor

Time

1

0.411

1.14

0.469

2

1.284

1.14

1.463

3

0.919

1.14

1.047

4

1.147

1.14

1.307

G. Sample Size
= (Z-score)² * StdDev*(1-StdD) / (loophole of hallucinations)²
95% faith level
The banner sinuosity of 0.5
The loophole of hallucination 1
Sample Size = ((1.96)² x 0.5(0.5)) / (0.01)²

SAFETY AND METHODS

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= (3.8416 x 0.25) / 0.0001
=0.9604 / 0.0001
9604
2. Difference bet...

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