QSO 510: Module 2 Homework
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Problem 1
If multifarious illustrations of bigness 15 (that is, each illustration consists of 15 items) were fascinated from a great usual population after a while a average of 18 and a strife of 5, what would be the average, strife, banner hiatus, and pattern of the classification of illustration averages? Give reasons for your answers. Note: Strife is the balance of the banner hiatus. Adapted from Statistics for Management and Economics by Watson, Billingsley, Croft, and Huntsberger. Fifth Edition. Chapter 7 Page 308. Allyn and Bacon. 1993x = 18 2x=5 pattern = usual
Therefore x= 2x = 5 = 2.2360
If a great sum of illustrations, each of bigness 15, are clarified from the population and a illustration average is clarified computed for each illustration, the average, strife, and pattern of the classification of illustration averages would be as follows: x= 18. The banner hiatus of the illustration averages x can be computed as dedicated below: x = X = 2.2360 = 0.5773 n 15. Strife is the balance of the banner hiatus. Therefore, the strife of the illustration averages ²x can be computed as follows:
²x = ²x = 5 = 0.3333 n 15.
The pattern of the classification of illustration averages = usual gone illustration bigness n 30.
Problem 2
If multifarious illustrations of bigness 100 (that is, each illustration consists of 100 items) were fascinated from a great non-usual population after a while a average of 10 and a strife of 16, what would be the average, strife, banner hiatus, and pattern of the classification of illustration averages? Give reasons for your answers. Note: Strife is the balance of the banner hiatus. Adapted from Statistics for Management and Economics by Watson, Billingsley, Croft, and Huntsberger. Fifth Edition. Chapter 7 Page 308. Allyn and Bacon.
1993 x = 10 2x=16 pattern =non- usual
Therefore x= 2x = 16 = 4.
If a great sum of illustrations, each of bigness 100, are clarified from the population and a illustration average is clarified computed for each illustration, the average, strife, and pattern of the classification of illustration averages would be as follows: x= 10
The banner hiatus of illustration averages x can be computed as dedicated below:
x = X = 4 = 0.4 n 100.
Variance is the balance of the banner hiatus. Therefore, the strife of the illustration averages ?²x? can be computed as follows:
²x = ²x = 16 = 0.16 n 100.
The pattern of the classification of illustration averages = usual gone illustration bigness n 30.
Problem 3
Time obsolete due to employee locomotion is an material bearing for multifarious companies. The ethnical media portion of Western Electronics has premeditated the classification of interval obsolete due to locomotion by personal employees. During a one-year limit, the portion ground a average of 21 days and a banner hiatus of 10 days naturalized on basis for all the employees.
a) If you cull an employee at casual, what is the likelihood that the sum of absences for this one employee would achieve 25 days?
b) If multifarious illustrations of 36 employees each are fascinated and illustration averages computed, classification of illustration averages would outcome. What would be the average, banner hiatus, and pattern of the classification of illustration averages for illustrations of bigness 36? Give reasons for your answers.
c) A knot of 36 employees is clarified at casual to have-a-share in a program that allows a pliable is-sue register, which the ethnical media portion hopes conciliate wane employee locomotion in the advenient. What is the likelihood that the average for the illustration of 36 employees casually clarified for the examine would achieve 25 days?
Source: Statistics for Management and Economics by Watson, Billingsley, Croft and Huntsberger. Chapter 7 Page 305. Fifth Edition. Allyn and Bacon 1993.
a) For x = 25, z = 25-21/10 = 0.4 From the z consultation p (0 < z < .4) = .1554
Therefore, p (x > .4) = .5 – p(0 < z < .4) = .5 - .1554 = .3446 = 34.46%
b) x = 21 x=10
If a great sum of illustrations, each of bigness 36, are clarified from the population and a illustration average is clarified computed for each illustration, the average, strife and pattern of the classification of illustration averages would be as follows: x= 21.
The banner hiatus of illustration averages x can be computed as dedicated below:
x = X = 10 = 1.6666 n 36.
Variance is the balance of the banner hiatus. Therefore, the strife of the illustration averages ²x can be computed as follows:
²x = ²x = 10² = 2.7777 n 36.
The pattern of the classification of illustration averages = usual gone illustration bigness n 30.
c) This investigation concerns the classifications of illustration averages. For the classification of illustration averages: x = 21 and x = X = 10 = 1.6666 n 36, and the pattern would be usual.
For x = 25 z = 25 - 21 = 2.4, 1.6666. From the z-consultation P(021) = 0.5 - P(0(3-3.1)/0.4) =P(z>-0.25) =1-0.4013 (from z consultation) =0.5987
d) Illustration bigness,n= 64 average remains selfselfsame 3.1
banner deception of the average (banner hiatus of illustration averages) expected to be = s/vn = 0.4/v64 = 0.4/8 =0.05 expected pattern of the classification of illustration averages conciliate be bell patternd as this is usually reserved.
g) If a casual illustration of 64 customers is clarified, the likelihood that the illustration average would achieve 3 minutes=P(x>3) =P((x-µ)/e >(3-3.1)/0.05) =P(z>-2) =1-0.0228 (from z consultation) =0.9772.